6dd889f9-2608-4b0d-8020-2a265b48d627 10 4 5 decimal

&[DATE] &[TIME] - &[FILENAME]

ΔT 5 Δ°F * :

Tank.min_vol 105.88 gal * :

For the empirical equation to work, this MUST be in BTU/hr!
This is why we carry units in engineering Load.instant 14.8 15.26 21 mat kW * :

Solve for the "RATE" 1 Load.instant 500 Tank.min_vol * rate * ΔT * BTU gal Δ°F * hr * / * ≡ rate 010 solve / vectorize min * min 5.2416 5.0836 21 mat

Why does this fail?  All I did was give it a name Rate 1 Load.instant 1 el 500 Tank.min_vol * rate * ΔT * BTU gal Δ°F * hr * / * ≡ rate 010 solve / vectorize min * : min 5.2416

How do I unnest a vectorized equation? R 1 Load.instant 500 Tank.min_vol * rate * ΔT * BTU gal Δ°F * hr * / * ≡ rate 010 solve / vectorize min * : vectorize min 5.2416 5.0836 21 mat

R 01 el el #

R 11 el #

R 1 el #

R vectorize min 5.2416 5.0836 21 mat

R vectorize 11 el 314.4969 s *

R vectorize 11 el R vectorize 21 el 21 mat 314.4969 s * 305.0167 s * 21 mat

Following jmG's example of "splitting" the load into separate solve blocks works! Why can I not do it with vectorize? Sometimes I do this with 20 loads and it looks like I would need a counter/loop program.

sol_rate 1 Load.instant 1 el 500 Tank.min_vol * rate * ΔT * BTU gal Δ°F * hr * / * ≡ rate 010 solve / 1 Load.instant 2 el 500 Tank.min_vol * rate * ΔT * BTU gal Δ°F * hr * / * ≡ rate 010 solve / 21 mat min * : min 5.2416 5.0836 21 mat

sol_rate min 5.2 5.1 21 mat

This is what I am after sol_rate 1 el min 5.2416

This is what I am after sol_rate 2 el min 5.0836

i model 1 Load.instant i el 500 Tank.min_vol * rate * ΔT * BTU gal Δ°F * hr * / * ≡ rate 010 solve / :

sol i 12 range S i el i model : for S 21 line :

sol 5.2416 5.0836 21 mat

sol min 5.2416 5.0836 21 mat